Math, asked by shravanibhat477, 10 months ago

85 cm
1. A wooden bookshelf has external dimensions as
follows: Height 110 cm, Depth
= 25 cm,
Breadth=85 cm (see Fig. 13.31). The thickness of
the plank is 5 cm everywhere. The external faces
are to be polished and the inner faces are to be
painted. If the rate of polishing is 20 paise per
cm and the rate of painting is 10 paise per cm²,
find the total expenses required for polishing and
painting the surface of the bookshelf.
25 cm
pls help pls pls​

Answers

Answered by ashu5201
1

Answer:

Step-by-step explanation:

outer surface =(100*2.5)*2+(85*2.5)*2cm^2

then =500+425=950cm^2

cost of polishing=950*20=19000/100=$190

Answered by ItzMissKomal
5

Answer:

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External length (l) of bookshelf=85㎝

External breadth (b) of bookshelf=25㎝

External height (h) of bookshelf=110㎝

External surface area of book shelf while leaving out the front face of the shelf=lh+2(lb+bh)

=(85×110)+2(85×25+25×110)

=9350+9750

=19100㎠

Area if front face=(85×110)−75×100+2(75×5)

=1850+760=2600㎠

Area to be polished=19100+2600=21700㎠

Cost of polishing=Rs. 21700×0.20=Rs.4340

Length, breadth and height of each row of bookshelf are

75㎝,20㎝ & 30㎝ respectively. From the figure Area to be painted in 1 row=2(l+h)b+lh

=2(75+30)20+75×30

=6450㎠

Area to be painted in 3 rows=3×6450=19350㎠

Total cost of painting=Rs.(19350×0.1)=Rs. 1935

Total expenses=Rs.

(4340+1935)=Rs. 6275(4340+1935)=Rs.6275

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