Question

85 litre of mixture contains milk and water in ratio 27 raised to 7 how much water is to be added to get a new mixture containing milk and water in ratio 3 raise to n​

Answer 1

ANSWER:

total mixture= 85 kg,

let: m = amount of milk

85 - m = amount of water.

ratio = 27:7 (milk:water),

27/7 =m/ (85−m)

Solve for m using cross-multiplication:

27(85−m)=7m

2295−27m=7m

2295=34m

m=135/2

135/2 kg milk, which means that we have:

water=85 - 135/2

=170/2 - 135/2

=35/2 kg water

water to be added to make the ratio 3:1.

Let n = amount of water added.

3/1=(135/2)/(35/2+n)

Now, solve for n. Again, start with cross multiplication:

3(35/2+n)=135/2

105/2+3n=135/2

3n=30/2

n=5

Answer (A) 5