86-S 45
find
flevatice ofx.
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Answer:
hey there
here is your answer
By using alternate angle property,
angle PRQ = angle RPS
Then,
angle RPS = 70°
Now in ∆PRS,
<RPS + <PRS + <PSR = 180°
70° + 45° + 7x - 5 = 180°
115° + 7x - 5 = 180°
110° + 7x = 180°
7x = 70°
x = 10
Hope you find it useful
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