Question

86. The height and the radius of the base of
a cone each are increased by 100%.The
volume of the cone then increases by
​

Answer 1

Answer:

Let the radius and height of the cone be R and H then

V¹=1/3×π×(R)²×(H)

When radius and heigh are increased by 100% then

V²= 1/3×π×(2R)²×(2H)

V²=8×1/3×π×(R)²×(H)

Hence,

V²=8×(V)¹

So. volume becomes eight times when radius and height are doubled