Question

86. The velocity vector of a particle moving in xy plane
is given by v=ti+xj. If initially the particle was
at origin then the equation of trajectory of the
projectile is
(1) 2x2 - 9y = 0 (2) 9x2 - 2y3 = 0
(3) 2x3 - 9y2 = 0 (4) 9x3 – 2y2 = 0

Answer 1

Answer:

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