86325_6 which value in place of _ then we are dividwd bu 11
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Step-by-step explanation:
for a no. to be a multiple of 11
its difference of the sums of its alternate digits must be equal to 11 or 0
so sum of odd placed digits
= 6+5+3+8
= 22
sum of even placed digits =
6+2+__
= 8 + __
difference = 22-8-__ = 11k
where k is a whole no.
14 -__ = 11k
if we input 3, we get 11 = 11k
thus k is equal to 1 and we get the answer
verification
now the no. is 8632536
sum of odd placed digits
= 8+3+5+6 = 22
sum of even placed digits
= 6+2+3 = 11
difference = 22-11 = 11
hence verified
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