8640 distributed in a b c d in a way that b have 5 times of a and c have 4 times of b and d have 8 times of c and 10 times of d is equal to all then find c
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Ans : 150
A+B+C=590, 5A=6B=8C;
8C/5 + 8C/6 + C = 590 ; 118C/30 = 590; C= 590*30/118 = 150
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