Question

8640 is a perfect cube or not

Answer 1

Hi there

Your answer is :-

$\sqrt[3]{8640}$

$\sqrt[3]{{12^3}\times{5}}$

$\sqrt[3]{12^3}\sqrt[3]{5}$

$12\sqrt[3]{5}\: ( Ans )$

Thank You

Answer 2

$\sqrt[3]{8640} \\ = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5} \\ = 2 \times 2 \times 3 \sqrt[3]{5} \\ = 12 \sqrt[3]{5} \\ it \: is \: not \: a \: perfect \: cube$