Question

87. In an arithmetic progression comprising 23
terms, the sum of the three terms in the middle
is 114 and the sum of the last three is 204. What
is the sum of the first three numbers ?
(A) 12
(B) 24
(C) 36
(D)48​

Answer 1

Answer:

24

Step-by-step explanation:

Ap has 23 terms

the middle terms are a+10d, a+11d,a+12d

given their sum is 114

114= 3a+33d. -----------------1

the last 3 terms are a+20d, a+21d,a+22d

sum is 204

204= 3a +63d-----------------------2

NOW, 2- 1

204-114= 63d-33d

90 = 30d

d= 3

therefore a=?

in ---1 3a +63d =204

3a = 204 -189

3a= 15

a= 5

now the first 3 terms are

a, a+d, a+2d

3a +3d

3 (5)+3 (3)

15+9

24

.... hope it helps you buddy

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