Question

8751 and 12560using euclid division algorithm by hcf

Answer 1

a = bq + r

12560 = 8751 x 1+ 3809

8751 = 3809 x 2 + 1133

3809 = 1133 x 3 + 410

1133 = 410 x 2 + 313

410= 313 x 1 + 97

313 = 97 x 3 + 22

97 = 22 x 4 + 9

22 = 9 x 2 + 4

9 = 4 x 2 + 1

4 = 1 x 4+0

Hcf is 1...

Answer 2

$hello \: mate$

12560=8751×1+3809

8751=3809×2+1133

3809=1133×3+410

1133=410×2+313

410=313×1+97

313=97×3+22

97=22×4+9

22=9×2+4

9=4×2+1

4=1×4+0

HCF=1