Question

8751 and 12560using euclid division algorithm by hcf

Answer 1

12560 = 8751 × 1 + 3809

8751 = 3809 × 2 + 1133

3809 = 1133 × 3 + 410

1133 = 410 × 2 + 313

410 = 313 × 1 + 97

313 = 97 × 3 + 22

97 = 22 × 4 + 9

22 = 9 × 2 + 4

9 = 4 × 2 + 1

4 = 1 × 4 + 0

Hence,

HCF = 1

Here is your answer...

Answer 2

Question -

8751 and 12560 using Euclid division algorithm by hcf.

Answer ==>

12560 = 8751 × 1 + 3809

8751 = 3809 × 2 + 1133

3809 = 1133 × 3 + 410

1133 = 410 × 2 + 313

410 = 313 × 1 + 97

313 = 97 × 3 + 22

97 = 22 × 4 + 9

22 = 9 × 2 + 4

9 = 4 × 2 + 1

4 = 1 × 4 + 0

Hence,

H•C•F = 1

here is your answer....