Math, asked by vicky52818, 1 year ago

8783638x75y99 is divisible by 88.find the largest value of y​

Answers

Answered by CarlynBronk
0

Answer with explanation:

It is given that, 8783638x75y99 is divisible by 88.

88=8 × 11=2×2×2×11

Sum of the digits should be divisible by both 11 as well as 2.

Sum of the digits = 8+7+8+3+6+3+8+x+7+5+y+9+9

                        = 73 +x+y

⇒73+x+y is divisible by 2 and 11.

⇒73 +x+y =77,because 77 is nearest number to 73, which is divisible by 11.

⇒x+y=77 -73

⇒x+y=4

But, 77 is not divisible by 2.

So, next number after 77, which is divisible by 11 and 2 both is 88.

⇒73 +x+y=88

⇒ x+y=88-73

⇒x+y=15

Since , x and y are both single digit number.We have to find largest value of y.

So, if , x=6 ,then y=15-6, then y=9, which is the largest value of y.

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