8783638x75y99 is divisible by 88.find the largest value of y
Answers
Answered by
0
Answer with explanation:
It is given that, 8783638x75y99 is divisible by 88.
88=8 × 11=2×2×2×11
Sum of the digits should be divisible by both 11 as well as 2.
Sum of the digits = 8+7+8+3+6+3+8+x+7+5+y+9+9
= 73 +x+y
⇒73+x+y is divisible by 2 and 11.
⇒73 +x+y =77,because 77 is nearest number to 73, which is divisible by 11.
⇒x+y=77 -73
⇒x+y=4
But, 77 is not divisible by 2.
So, next number after 77, which is divisible by 11 and 2 both is 88.
⇒73 +x+y=88
⇒ x+y=88-73
⇒x+y=15
Since , x and y are both single digit number.We have to find largest value of y.
So, if , x=6 ,then y=15-6, then y=9, which is the largest value of y.
Similar questions