Question

88. Find AH in terms of KJ for the following
reaction from the given data
M(g) + 2X(g) → M2+(g) + 2X-(g)
(IE), of M(g) = 705 KJ mol-1
(IE), of M(g) = 1151 KJ mol-!
(EA), of X(g) = -328 KJmol-1
1) 120 KJ
2) 512 KJ
3) 1200 KJ
4) 110 KJ
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Answer 1

Answer:

Mg(g)⟶ Mg +2(g) + 2e - is Mg→ Mg + → Mg+2 so energy required for the reaction is 178 + 348 = 526 kcal/mol.