Question

88 students took part in an English competition. 72 of them were men. What percentage of all participants were men?

Answer 1

Total students = 88
number of men = 72

% of men = $\frac{number\ of\ men}{total\ students} \times 100 = \frac{72}{88} \times 100=81.82$

So 81.82% of the participants were men.

Answer 2

Total students is 88. Number of men is 72. To calculate percentage, (number of men/total students)* 100 is done. That is , (72/88)*100 = (9/11)*100 = 900/11 = 81.8 %