Question

888*[27\{56+(14\2)}]​

Answer 1

Answer:

A dice is thrown twice. What is the probabilities of getting sum as 2.3,4,5,6,7,8,9,10,11,12 on each dice

Answer 2

$888 \times (27 \div (56 + (14 \div 2)))$

$888 \times (27 \div (56 + 7))$

$888 \times (27 \div 63)$

$888 \times \frac{3}{7}$

$\frac{2664}{7}$

$380 \frac{4}{7}$