Question

88g of CO2
No of molecule
No of mole
No of C atom
No of O atom.​

Answer 1

Answer:

Molecular mass of CO2=44g(12+2×16)

No. of moles=88/44

=2 moles

No. of molecules=2NA

2×6.022×10^23

12.044×10^23

No. of Course atom =2

No. of O atoms=4

Answer 2

Answer:

Mark brilliant....mmmmmmm