Question

88Ra226 experiences three alpha decay. find the number of neutrons in the daughter elements.
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Answer 1

Answer:

Solution :

α-decay : zXA→z−2YA−4+2He4

3α-decay:

zXA→z−6YA−12+3(2He4)

∴88Ra226→82Pb214+32He4(or)

88Ra226→82X214+32He4

Explanation:

Answer 2

Answer:

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