Question

89. A large cylinder of helium filled at 2000 mm of Hg
had a small orifice through which helium escaped
into evacuated space at the rate of 6.4 moles/hour
How long would it take for 10 mole of CO to leak
through a similar orifice if the CO were confined at
the same pressure?
(a) 6.5 hour
(b) 8.4 hour
(c) 4.2 hour
(d) 12.4 hour​

Answer 1

Answer:

The time it take for 10 mole of CO to leak

through a similar orifice if the CO were confined at

the same pressure is t = 10/2.4 ≈ 4.2 hour (Option C)

Explanation:

Let assume that the rate at which helium escaped  into evacuated space is rHe and also assume that the rate at which carbon monoxide escaped  into evacuated space is rCO.

Given, rHe= 6.4 moles/hour

Now we need to know rCO.

We know atomic mass of helium M(He)=4 and atomic mass of carbon monoxide is M(CO)=28

Then we can say,

rHe/rCO = M(CO)/M(He)=√28/√4=2.65  

OR, rCO = rHe/2.65 = 6.42.65 = 2.4 mole/hour.

At last the time it take for 10 mole of CO to leak

through a similar orifice if the CO were confined at

the same pressure is t = 10/2.4 ≈ 4.2 hour.