89. Find the equivalent resistance across the two ends A and B of this circuit.
R1= 2ohms to R8=2ohms
Answers
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If R₁ to R₈ are in series ,
Equivalent resistance = R = R₁ + R₂ + ....... R₈
R = 2 + 2 + 2 ..... + 2
R = 2 × 8
R = 16Ω
If R₁ to R₈ are in parallel ,
Equivalent resistance = 1/R = 1/R₁ + 1/R₂ + ..... 1/R₈
1/R = 1/2 + 1/2 + 1/2 + ........ 1/2
1/R = 8 × 1/2
1/R = 8/2 = 4
R = 1/4 Ω = 0.25Ω
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Answer:
No. of connected resistors - 8
Resistance of each resistor - 2 Ω
Case I : When connected in series.
R eq. = R1 + R2 ..... R8
R eq. = No. of connected resistors X
Resistance of each resistor. (THIS FORMULA WORKS ONLY WHEN RESISTANCE OF EACH RESISTORS ARE SAME)
Req. = 2 X 8
Req. = 16Ω
Case II : When connected in parallel.
No. of connected resistors - 8
Resistance of each resistor - 2 Ω
R eq. = 1/Resistance of each resistor X No. of connected resistors (THIS FORMULA WORKS ONLY WHEN RESISTANCE OF EACH RESISTORS ARE SAME)
R eq. = 1/2 X 8
R eq. = 4
R eq. = 1/4 Ω
R eq. = 0.25Ω
Hope it helps you.
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