896 mL of a mixture of CO and Co, weigh 1.28 g
at NTP. Calculate the volume of Co, in the mixture
at NTP. ANS. 224ml
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Answer:
Answer: 224 ml
Explanation: Let's assume 'x' ml CO2
and hence '896-x' ml CO.
Also assume 'y' g CO2
and hence '1.28-y' g CO.
by equating moles of CO2 i.e.
x/22400= y/44
and by equating moles of CO i.e.
896-x/22400 = 1.28-y/28
now by solving the two equations two variables we get y=11/25 and therefore x= 224 ml.
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