Question

896 ml of a mixture of CO and CO2 weigh 1.28gms at NTP. Calculate the volume of CO2 in the mixture at NTP.

Answer 1

Hi friend,

# 0.01 mole of Co and 0.03 mole of Co2

Explanation :-

you can get the n° di mol of the mixture of Co and Co2 from the gases law where one mole occupy at NTP 22.4 L.

n = p.V/R.T = 1 atm × 0.896L/ 0.082. L×atm/mol ×k × 273k = 0

0.400 mol

X + Y = 0.40 and

X × 28 + y × 44 = 1.28 g

from the first equation you have X = 0.04 - Y and in 2nd

1.12 + ( 44-28 ) Y = 1.28

Y = ( 1.28 - 1.12 ) /16 = 0.01 mole of Co and than 0.03 of Co2 ....i hope it helps you

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