896 ml of a mixture of CO and CO2 weigh 1.28gms at NTP. Calculate the volume of CO2 in the mixture at NTP.
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CO=12+6=28g
CO2=12+32=44g
28g of CO2 has volume 22400 1g of CO2 has volume 22400/44ml = 509.09ml
CO2=12+32=44g
28g of CO2 has volume 22400 1g of CO2 has volume 22400/44ml = 509.09ml
AaanyaKandwal:
Perfect answer
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