Math, asked by sahasradomala, 6 months ago

8a^3+125b^3-64c^3+120abc

Answers

Answered by Bidikha

4

Answer:

=8a³+125b³-64c³+120abc

=(2a)³+(5b)³+(-4)³-3×2a×5b×(-4)

=(2a+5b-4)[(2a)²+(5b)²+(-4)²-2a×5b-5b×(-4)-(-4)×2a

=(2a+5b-4)(4a²+25b²+64-10ab+20b+8a)

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