Question

8a^3-b^3-4ax+2bx factorise

Answer 1

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Answer 2

Here's your answer!!

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${8a}^{3} - {b}^{3} - 4ax + 2bx$

$({(2a)}^{3} - {b}^{3}) - 2x(2a - b)$

We know that,

$( {a}^{x} - {b}^{x}) = (a - b)( {a}^{2} + ab + {b}^{2} )$

We will use this identity to solve this question,

$(2a - b)( ({2a})^{2} +( 2a \times b) + {b}^{2} ) - 2x(2a - b)$

$(2a - b)( {4a}^{2} + 2ab + {b}^{2} ) - 2x(2a - b)$

$(2a - b)( {4a}^{2} + 2ab + {b}^{2} - 2x )$

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Hope it helps you!! :)