Question

8a^3-b^3-4ax+2bx
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Answer 1

Answer:

The answer is given below :

Now,

8 {a}^{3} - {b}^{3} - 4ax + 2bx \\ \\ = ( {(2a)}^{3} - {b}^{3} ) - 2x(2a - b) \\ \\ = (2a - b)( {(2a)}^{2} + (2a \times b) + {b}^{2} ) - 2x(2a - b) \\ \\ = (2a - b)(4 {a}^{2} + 2ab + {b}^{2} ) - 2x(2a - b) \\ \\ = (2a - b)(4 {a}^{2} + 2ab + {b}^{2} - 2x)

which is the required factorization.

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