Math, asked by prosserjordyn, 4 months ago

8a + 3b - 10 + c² when a = 2, b = 5, and c = 5?

Answers

Answered by Anonymous
1

Answer:

46 is the answer

Step-by-step explanation:

hope it helps!!

Answered by Ladylaurel
2

Correct Question :-

8a + 3b - 10 + c² when

  • a = 2
  • b = 5
  • c = 5

Answer :-

  • The required number is 46.

Step-by-step explanation ::

Given that,

8a + 3b - 10 + c²

  • a = 2
  • b = 5
  • c = 5

Solution ::

=> 8a + 3b - 10 + c²

=> 8*2 + 3b - 10 + c²

=> 16 + 3*5 - 10 + c²

=> 16 + 15 - 10 + c²

=> 16 + 15 - 10 + 5²

=> 16 + 15 - 10 + 25

=> 16 + 5 + 25

=> 16 + 30

=> 46

The required number is 46.

Now, Verification

  • 8a + 3b - 10 + c² = 46

We have,

  • L.H.S = 8a + 3b - 10 +
  • R.H.S = 46,

By, putting the values of a, b and c,

=> 8a + 3b - 10 + c²

=> 8*2 + 3b - 10 + c²

=> 16 + 3*5 - 10 + c²

=> 16 + 15 - 10 + c²

=> 16 + 15 - 10 + 5²

=> 16 + 15 - 10 + 25

=> 31 - 10 + 25

=> 21 + 25

=> 46

Therefore,

  • L.H.S = 46

And, we have R.H.S = 46, Therefore,

L.H.S = R.H.S

Hence, Verified!

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