Question

8a - 3b+11c; 5b - 6a + 7c and 9c + 2a -8b find the sum of the following​

Answer 1

Answer:

The sum of 8a - 3b+11c, 5b - 6a + 7c, and 9c + 2a -8b is 4a - 6b + 27c

Step-by-step explanation:

We have to find the sum of 8a - 3b+11c, 5b - 6a + 7c, and 9c + 2a -8b.

Sum = (8a - 3b + 11c) + (5b - 6a + 7c) + (9c + 2a - 8b)

= 8a - 6a + 2a - 3b + 5b - 8b + 11c + 7c + 9c

= 10a - 6a - 11b + 5b + 20c + 7c

= 4a - 6b + 27c

Sum = 4a - 6b + 27c

∴ The sum of 8a - 3b+11c, 5b - 6a + 7c, and 9c + 2a -8b is 4a - 6b + 27c