8a cube- 2a square b- 15ab square factorise
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6
See the attached fil
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kvnmurty:
how did you get to know that you have to split -2 a^2 b into -12 a^2 b and +10 a^2 b ?? is there a method you used. Please mention that.
you have to take "a" out as a factor from the first factor... there are three factors not two.
Whenever it is a trinomial we used splitting method that is factorising method
Answered by
10
Hello,
8a³-2a²b-15ab²
we can write it as:
8a³-2a²b-3·5ab²
We collect to common factor:
a(8a²-2ab-3·5b²)
yet:
a(2a-3b)(4a+5b)
bye alessre :-)
8a³-2a²b-15ab²
we can write it as:
8a³-2a²b-3·5ab²
We collect to common factor:
a(8a²-2ab-3·5b²)
yet:
a(2a-3b)(4a+5b)
bye alessre :-)
please show the middle term splitting process. That is very important. how to get the last step from the earlier step... Without explanation user is lost.
pls explain that step.
answer is very correct.
8x(-15) : memiliki faktor-faktor 10 dan - 12, yang apabila dijumlahkan harus tepat sama dengan koefisien suku tengah xy yaitu 10 + (- 2) = - 2
then: 8a² - 12ab + 10ab - 15b²
= 4a(2a - 3b) + 5b (2a - 3b)
= (4a + 5b) (2a - 3b)
= 4a(2a - 3b) + 5b (2a - 3b)
= (4a + 5b) (2a - 3b)
Always multiply 1st n the last nos that means u get 120 n keep in mind middle term which is 2 ::now u hve to take two nos su h that when u multipy u should get 120 n when u add or subtract u should get 2
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