Question

8a power3-27b power3​

Answer 1

Answer:

Put this in the form

a

3

+(3b)

3

+(2c)

3

−3a(3b)(2c)

Use the familiar factorisation to get

a

3

+27b

3

+8c

3

−18abc=(a+3b+2c)[a

2

+(3b)

2

+(2c)

2

−a(3b)−3b(2c)−(2c)a]

Now simplify and get

a

3

+27b

3

+8c

3

−18abc=(a+3b+2c)(a

2

+9b

2

+4c

2

−3ab−6bc−2ca)

Answer 2

this is the correct answer..so its help you