Question

8a²-18m²
factorise by first taking out the common factor and then applying the identity a²-b²?​

Answer 1

Answer:

8a²-18m² = 2  (2a -  3m) (2a +  3m)

Step-by-step explanation:

Identity applying : a²-b² = ( a - b)(a + b)

Given: 8a²-18m²

Solve by using identity

8a²-18m²

Take common 2

= 2 (4a²- 9m²)

Put in a²-b² form

= 2 [(2a)²- (3m)²]

Use identity for solving

= 2  (2a -  3m) (2a +  3m)  [∵ a²-b² = ( a - b)(a + b)]

So, 8a²-18m² = 2  (2a -  3m) (2a +  3m)