Math, asked by chexxrymilk, 23 days ago

8a²- [3a² + 3a² - (a² - 4a²)}]
solve​

Answers

Answered by vr106367
1

Answer:

WE CAN DO BY BRACKET RULE.

8a²-[6a²-(-3a²)]

= 8a²-6a²+3a²

= 5a²

Answer = 5a²

Step-by-step explanation:

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Answered by preeti353615
1

Answer:

8a²- [3a² + 3a² - (a² - 4a²)}] = -1a²

Step-by-step explanation:

8a²- [3a² + 3a² - (a² - 4a²)}]

remove first bracket and change sign

= 8a²- [3a² + 3a² - a² + 4a²]

Solve second bracket

= 8a²- [3 + 3 - 1 + 4 ]a²

= 8a²- [3 + 3 - 1 + 4 ]a²

= 8a²-9a²

= (8-9)a²

= -1a²

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