Math, asked by nisbaronak, 3 months ago

(8a³÷27x-³)⅔×(64a³÷27×-³)-⅔
Indices​

Answers

Answered by ItzMissKomal
3

Answer:

(8a^3 ÷ 27x^-3)^2/3 * (64a^3 ÷ 27x^-3)^-2/3

= (2a * 3x)^[3*2/3] * (4a * 3x)^[3*-2/3]

= (6ax)^2 * (12ax)^-2

= 6a^2x^2/

12a^2x^2

= 1/2

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