Question

8a3b3-27 factorization

Answer 1

(2ab)3 - (3)3
= (2ab-3)(2ab-3)(2ab-3)

Answer 2

$8 {a}^{3} {b}^{3} - 27$
It could be written as
${2ab}^{3} - {3}^{3}$
$now \: its \: in \: form \: of \: {a}^{3} - {b}^{3}$
and as we know that,
${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$
Therefore, the whole equation becomes:

$(2ab - 3)(4 {a}^{2} {b}^{2} + 3ab + 9)$