Question

(8abc − 16ab) ÷ (−8ab) =

Answer 1

Answer:

$\frac{8abc - 16ab}{ - 8ab} \\ \\ = \frac{8ab(c - 2)}{ - 8ab} \\ \\ = - (c - 2)$

Answer 2

Answer:

We get the  Final answer is $(8abc-16ab)$  ÷ $(-8ab)$$=-(c-2)$

Step-by-step explanation:

This is the division sum.

That is,     $(8abc-16ab)$ ÷ $(-8ab)$ $=\frac{8abc-16ab}{(-8ab)}$

here we should take the common value in the numerator. In the numerator, $ab$ is the common term and numerical value $8$ also a common value.So that,

                                     $\frac{8abc-16ab}{(-8ab)}=\frac{8ab(c-2)}{(-8ab)}$

Now cancel $8ab$ in the numerator and denominator. Then we get te following equation.

                                        $\frac{8ab(c-2)}{(-8ab)}=\frac{c-2}{(-1)}$  

It can be written as,         $\frac{8ab(c-2)}{(-8ab)}=-(c-2)$