Question

(8acube–1)divided by (2a–1)​

Answer 1

(8a³-1)/(2a-1),

We can write it as,

[(2a)³-(1)³]/(2a-1),

now applying

(x³-y³)=(x-y)(x²+y²+xy) in the numerator,

so we have

[(2a-1)(4a²+1+2a)]/(2a-1),

(4a²+1+2a)