Math, asked by gpchawberia2, 8 months ago

(-8b^2+4b-8)+(-2b^2-5b-1), when b=?​

Answers

Answered by Rudranil420
54

Answer:

➡(-8b² +4b-8)+(-2b² -5b-1)

=> -8b²+4b-8-2b²-5b-1=0

=> -8b²-2b² +4b-5b-8-1=0

=> -10b² -1b-9=0

=> 10b² + b +9 = 0

Step-by-step explanation:

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