Question

(8b6+4c3)+(2b5-7c3)=​

Answer 1

Answer:

(b+c)=141

Step-by-step explanation:

1. $(8b6 + 2b5) + (4c3 - 7c3) \\ b(86 + 25) + c(43 - 73) \\ b(111) +c (30) \\( b + c)= 141$

Answer 2

Correct Question :-

Solve — $ \rm{(8b^{6}+4c^{3}) + (2b^{5}-7c^{3})}$

Correct Answer :-

Here, we can,

$\rm{(8 {b}^{6} + 4 {c}^{3} ) + (2 {b}^{5} - 7 {c}^{3}) }$

Combine $\rm{4c^{3} }$ and $ \rm{-7c^{3}}$ to get $ \rm{-3c^{3}}$.

$\to \rm{8b^{6}-3c^{3}+2b^{5} }$

∴ Hence, the value for $ \rm{(8b^{6}+4c^{3}) + (2b^{5}-7c^{3})}$ will be $ \rm{8b^{6}-3c^{3}+2b^{5} }$.