Question

(8g-11g) (-5 ) +6g factorise​

Answer 1

Step-by-step explanation:

(8g-11g)(-5)+6g=0

(-3g)(-5)+6g=0

15g+6g=0

21g=0

g=0

Answer 2

Answer:

$\large\boxed{15g+6g=21g}$

Step-by-step explanation:

To solve this problem, first you have to find the factors of (8g-11g)(-5)+6g from left to right. You can also used solve with distributive property.

$\large\boxed{\textnormal{Distributive property}}$

$\displaystyle a(b+c)=ab+ac$

Given:

(8g-11g)(-5)+6g

Solution:

First, thing you do is remove parenthesis.

(-b)=-b

$\displaystyle -(8g-11g)*5+6g$

Secondly, add numbers from left to right.

$\displaystyle (8g-11g)*5$

$\displaystyle 8g-11g=-3g$

$\displaystyle 5(-3g)$

$\displaystyle -3g*5$

Thirdly, multiply numbers from left to right.

$\displaystyle 3*5=15$

$\displaystyle (8g-11g)*5=-15g$

$\displaystyle -(-15g)+6g$

Change minus sign to add sign (positive sign.)

$\displaystyle 15g+6g=\boxed{21g}$

So, the correct answer is 15g+6g=21g.