Question

8g of a gas at STP occupies 5.6 L hense, number of moles present in 64g of the gas will be

Answer 1

Answer:

4moles.

Explanation:

in 8g there are1/4 moles.

therfore in 64g ∛64 is 4.

so there are 4 moles present in 64 g.

Answer 2

Answer: Number of moles present in 64g of the gas are 2 moles.

Explanation:

5.6 Litre is occupied by 8 gram gas.

S,22.4 litre is occupied by  

                                        $=$   $\frac{8 * 22.4}{5.6}$

                                        $= 32g$

which is molar mass of gas.

1 mole of gas occupies $22.4Litres$ and mass is $32grams.$

Number of mole of gas in 64 gram $= \frac{amount }{molar mass}$

                                                           $=\frac{64}{32}$

                                                         $= 2 moles$

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