8g of a metal oxide contains 3.2 g of oxygen, then
oxide can be
(1) Mgo
(2) LI2O
(3) Na2o
(4) CaO
Answers
Answered by
3
Answer:
1 . MgO
Explanation:
we can find it by % of oxygen.
Answered by
1
Answer:see here option 4 is correct. Cao.
Explanation:see, amount of metal is(8-3.2)or 4.8 gram, so from stoichiometry only Cao is nearby, approximately (4.0gram of CA involved) by this data, so undoubtedly it will be the correct answer.
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