Question

8g of carbon monooxide no. of moles and no. of particles

Answer 1

m = 8g
M = CO = 12+16 = 28

n = m / M

= 8 / 28 = 2/7

n = 0.28

No. Of moles = 0.28

No. Of particles is given by

1 mole of CO contains 6.022 * 10^23 particles.

So 0.28 moles of CO contains

0.28 * 6.022 * 10^23 particles

1.68 * 10^23 particles


Thanks

Answer 2

m = 8g

M = CO = 12+16 = 28

n = m / M

= 8 / 28 = 2/7

n = 0.28

No. Of moles = 0.28

No. Of particles is given by

1 mole of CO contains 6.022 * 10^23 particles.

So 0.28 moles of CO contains

0.28 * 6.022 * 10^23 particles

1.68 * 10^23 particles