Question

8g of o2 has the same number of molecules as in 11g co2 22g co2 7g co 14 co

Answer 1

11g of co2 as the no of moles In both are absolutely same so molecules will be also same

Answer 2

Answer: 11 g $CO_2$ and 7 g $CO$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Equal number of moles contains equal number of molecules.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of oxygen}=\frac{8g}{32g/mol}=0.25moles$

a. 11 g $CO_2$

$\text{Number of moles of carbon dioxide}=\frac{11g}{44g/mol}=0.25moles$

b. 22 g $CO_2$

$\text{Number of moles of carbon dioxide}=\frac{22g}{44g/mol}=0.5moles$

c. 7 g $CO$

$\text{Number of moles of carbon monoxide}=\frac{7g}{28g/mol}=0.25moles$

d. 14 g $CO$

$\text{Number of moles of carbon monoxide}=\frac{14g}{28g/mol}=0.5moles$

Thus 11 g $CO_2$ and 7 g $CO$ contains same number of molecules as in 8 g of $O_2$