Chemistry, asked by nunu4836, 10 months ago

8g of sulphur is completely burnt to get sulphur dioxide. The number of molecules of SO2 obtained is

Answers

Answered by talhahpeerbhai
5

Answer:

150550000000000000000000 molecules

Explanation:

Reletive Atomic Mass of Sulphur = 32g

Reletive Atomic Mass of Oxygen= 16g

Since No. of moles = Mass / Relative Molecular Mass,

No. of moles of S burnt = 8g/32g

= 0.25 moles

From the equation,

1 mole of Sulphur will react with 1 mole of O2 to form 1 mole of S02

Hence,

0.25 mole of Sulphus will react with .025 mole of O2 to form 0.25 mole of SO2

Mass of oxygen consumed = 0.25 moles x (2 x 16g)

= 8g

Mass of SO2 produced = 0.25 moles x ( 32g + (2 x 16g))

=0.25 mole x 64g

=16g

And we know there is 0.25 moles of SO2 so we can use Avogadro's number 6.022 x 10^23 to calculate how many molecules there are. 0.25 x 6.022 x 10^23 which would equal to 150550000000000000000000 atoms/molecules

Answered by saimanaswini64
0

Answer:

150550000000000000000000 molecules

Explanation:

Reletive Atomic Mass of Sulphur = 32g

Reletive Atomic Mass of Oxygen= 16g

Since No. of moles = Mass / Relative Molecular Mass,

No. of moles of S burnt = 8g/32g

= 0.25 moles

From the equation,

1 mole of Sulphur will react with 1 mole of O2 to form 1 mole of S02

Hence,

0.25 mole of Sulphus will react with .025 mole of O2 to form 0.25 mole of SO2

Mass of oxygen consumed = 0.25 moles x (2 x 16g)

= 8g

Mass of SO2 produced = 0.25 moles x ( 32g + (2 x 16g))

=0.25 mole x 64g

=16g

And we know there is 0.25 moles of SO2 so we can use Avogadro's number 6.022 x 10^23 to calculate how many molecules there are. 0.25 x 6.022 x 10^23 which would equal to 150550000000000000000000 atoms/molecules

Explanation:

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