8gm Methane and 2gm of hydrogen and mixed and kept at 760 mm pressure at 273 K then total volume occupied will be ?
Pls help
Answers
Given :-
8gm Methane and 2gm of hydrogen and mixed and kept at 760 mm pressure at 273 K
To Find :-
Total volume
Solution :-
Finding moles first
For methane
For hydrogen
Now
CONCEPT: Volume is the space occupied by any matter.
- Ideal gas law i.e. PV=nRT
GIVEN: Given mass of methane= 8gm
Given mass of hydrogen= 2gm
Pressure= 760 mm
Temperature= 273 K
FIND: We have to find total volume occupied by the moles of given mixture.
SOLUTION:
no. of moles of methane= 8/16
= 0.5
no. of moles of hydrogen= 2/1
= 2
Total no. of moles in the mixture= 2.5
From ideal gas law: PV = nRT
V = nRT/P
V =2.5×0.0821×273/ 1
V = 56.03 Litres
Hence total volume occupied by the moles of given mixture is 56.03 Litres.
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