(8î+2j^+3k^).(6î-3j^-9k^)
Answers
Answered by
1
Answer:
15
Explanation:
(8î+2j^+3k^).(6î-3j^-9k^)
= 48i²-24ij-72ik+12ji-6j²-18jk+18ki-9kj-27k²
=48*1-24*0-72*0+12*0-6*1-18-0+18*0-9*0-27*1(since, dot product of i²,j²,k²=1 and i.j,j.k,k.i=0)
=48-6-27
=15
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