Question

(8k+4), (6k-2), (2k-7) are three consecutive terms of an A.P., the value of 'k' is. *K​

Answer 1

Answer:

Step-by-step explanation:

Given,

8k+4, 6k-2 and 2k-7 be 3 consecutive terms of an AP.

a2-a1 = a3-a2

⇒ (6K-2)-(8K+4) = (2K-7) - (6K-2)

= 6K-2-8K-4= 2K-7-6K +2

= -2K-6 = -4K-5

= 2K = 1

= K = 1/2

HOPE IT HELPS YOU....