Question

8ka power x _1by 2ka power x_1equal to64

Answer 1

$\frac{ {8}^{x - 1} }{ {2}^{x - 1} } = 64 \\ \frac{ {2}^{3(x - 1)} }{ {2}^{x - 1} } = 64\\ {( {a}^{x} )}^{y} = {a}^{xy} \\ \frac{ {a}^{x} }{ {a}^{y} } = {a}^{x - y} \\ = {2}^{3(x - 1) - (x - 1)} = 64 \\ 64 = {2}^{6} \\ {2}^{2x - 2} = {2}^{6} \\ 2x - 2 = 6 \\ x = 4 \\ \frac{ {8}^{x} }{ {2}^{x} } = 64 \\ \frac{ {2}^{3x} }{ {2}^{x} } = {2}^{6} \\ {2}^{2x} = {2}^{6} \\ x = 3$
hope it helps