Question

8L of 0.4M aqueous solution of KOH is mixed with 4L of 1.0M aqueous solution of KOH. The molarity of the resulting solution is ....​

Answer 1

Answer:

0.6M

explanation

no of mole of KOH in 8L of 0.4M = 3.2

„. „. „ „ KOH in 4L of 1.0M = 4.0

after mixing no of mole of KOH in 12L = 7.2

so, the molarity of the resulting solution = 7.2÷ 12 = 0.6M