Math, asked by mostakim2011islam, 29 days ago

(8m+1)^2-(16m+2)(3n-2)+(3n-2)^2​

Answers

Answered by sreeraaga2506
0

Answer:

Step-by-step explanation:

(8m+1)²

It is in the form of (a+b)²= a²+b²+2ab

⇒(8m)²+(1)²+2(8m)(1) ⇒ 64m²+1+16m

(16m+2)(3n-2)

⇒48mn-32m+6n-4

(3n-2)²

It is in the form of (a-b)²=a²+b²-2ab

⇒(3n)²+(2)²-2(3n)(2)

⇒9n²+4-12n

Now,(8m+1)^2-(16m+2)(3n-2)+(3n-2)^2

⇒64m²+1+16m-(48mn-32m+6n-4)+9n²+4-12n

⇒64m²+1+16m-48mn+32m-6n+4+9n²+4-12n

⇒64m²+9n²-48mn+48m-21n+9

Hope it helps you.

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