8M II. Answer the following 1. An object 6cm in size, 10cm in front if concave mirror, of focal length 5cm, find image distance and magnification ?
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1cm
Given,
Size of object ho=5cm
Size of the image hi=?
Focal length, f=−10cm
Object distance u=−60cm
Image distance v=?
Using mirror formula,
f1=v1+u1
−101=v1+−601
v1=60−6+1
v=−12cm
Hence, the position of the object is at 12 cm in front of the mirror.
Magnification (M)=hohi=u−v=−6012=−0.2
hi=−0.2×ho
hi=−0.2×5=−1cm
Height of inverted image is 1cm.
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